(x^2+3)^2+21=10x^2+30(x2+3)2+21=10x2+30

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Solution for (x^2+3)^2+21=10x^2+30(x2+3)2+21=10x2+30 equation: 



(x^2+3)^2+21=10x^2+30(x2+3)2+21=10x^2+30

We move all terms to the left:

(x^2+3)^2+21-(10x^2+30(x2+3)2+21)=0

We add all the numbers together, and all the variables

-(10x^2+30(+x^2+3)2+21)+(x^2+3)^2+21=0



We calculate terms in parentheses: -(10x^2+30(+x^2+3)2+21), so:

10x^2+30(+x^2+3)2+21

We multiply parentheses

10x^2+60x^2+180+21

We add all the numbers together, and all the variables

70x^2+201

Back to the equation:

-(70x^2+201)



We get rid of parentheses

-70x^2+(x^2+3)^2-201+21=0

We add all the numbers together, and all the variables

-70x^2+(x^2+3)^2-180=0

We move all terms containing x to the left, all other terms to the right

-70x^2+(x^2+3)^2=180

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